Answer:
-0.1 Joules
Step-by-step explanation:
Here, the kinetic energy of the spring and glider is conserved.
So, we get
KE of spring + Work done by friction = Change in momentum of glider
![(1)/(2)k(x_f^2-x_i^2)+W_f=(1)/(2)m(v^2-u^2)\\\Rightarrow W_f=(1)/(2)m(v^2-u^2)-(1)/(2)k(x_f^2-x_i^2)\\\Rightarrow W_f=(1)/(2)0.4(1^2-0^2)-(1)/(2)20(0.2^2-0.1^2)\\\Rightarrow W_f=-0.1\ Joules](https://img.qammunity.org/2020/formulas/physics/college/2rlfuh47qz9qcvan7kv1dkv2tu31qe9ma2.png)
The work done by friction during that segment of motion is -0.1 Joules