Answer:
94.9 grams of krypton gas will occupy 2.55 liters at 1.25 atm
Step-by-step explanation:
According to Boyle - Mariotte's law, for a constant temperature system, the pressure changed inversely proportional to the volume. By decreasing the volume of the container, the pressure increases because the molecules collide more against the wall of the container
This is the Ideal Gas law equation.
P.V = n.R.T
In the first case, the gas occupes 0,13 moles
3,75L . 0,750 atm = n . 0,082L.atm/mol.K . 255K
(3,75L . 0,750 atm) / 0,082mol.K/L.atm . 255K = n = 0,13 moles
The new moles that the gas occupes will be higher than 0,13 so according to Boyle-Mariotte's law ( at the same T°, we suppose that)
P1 . V1 = P2 . V2
P1.V1 = n1 . R . T
P2 . V2 = n2 . R . T
(P1. V1) / R. T = (P2 . V2) / n2 .R .T
R and T are the same on both sides so we cancel them.
(P1. V1) = (P2 . V2) /n2
n2 = (P2 . V2) / (P1. V1)
n2 (2,55 . 1,25) / (3,75 . 0,750)
n2= 1,13 moles
Molar mass of Kr = 83,80 g/m
Molar mass . moles = gr ---> 83,80 g/m . 1,13 moles = 94,9 g