Question

What is the net ionic equation for the reaction that is represented by the following total ionic equation? 6Na+2PO4+3Ca+6Cl--->6Na+6Cl+Ca3(PO4)2

Answer 1

B) 2PO3/4- + 3Ca^2+ ----> Ca3(PO4)2

Step-by-step explanation:

This is the answer because 6Na+ and 6Cl- are spectator ions (they're on both sides of the equation and remain unchanged) and you have to remove them from the equation in order to get the net ionic equation.

Answer 2

Answer: The net ionic equation is written below.

Step-by-step explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The given total ionic equation follows:

`6Na^+(aq.)+2PO_4^(3-)(aq.)+3Ca^(2+)(aq.)+6Cl^-(aq.)\rightarrow 6Na^+(aq.)+6Cl^-(aq.)+Ca_3(PO_4)_2(s)`

As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

`3Ca^(2+)(aq.)+2PO_4^(3-)(aq.)\rightarrow Ca_3(PO_4)_2(s)`

Hence, the net ionic equation is written above.