Question

An animal cell with a solute potential of -1.2 bars is placed into an open beaker containing a solution with a solute potential of -3.8 bars. What is the resulting movement of water in this example? A) Water will move into the cell because the solution is hypotonic to the cell. B) Water will not move into nor out of the cell because the solution and the cell are isotonic. C) Water will move out of the cell because the beaker solution has a lower water potential than the cell. D) Water will move into the cell because the cell has a higher water potential than the solution in the beaker.

Answer 1

Water will move into the cell because the solution is hypotonic to the cell.

Step-by-step explanation:

In this example, the animal cell with a solute potential of -1.2 bars is in a beaker containing a solution with a solute potential of -3.8 bars. The cell is placed in a hypotonic solution, which means that the solution has a lower water potential than the cell. Water will move into the cell from the beaker solution to equalize the solute concentration on both sides of the cell membrane.

Water will move out of the cell on the grounds that the measuring glass arrangement has a lower water potential than the phone.

In synopsis, because of the distinction in solute potential, water will move out of the creature cell and into the arrangement in the receptacle, as water generally moves from areas of higher water potential to bring down water potential.

Answer 2

The correct answer is A water will move into the cell because the solution i hypotonic to the cell.

Step-by-step explanation:

The solute potential of the cell is -1.2 bars whereas the solute potential solution of the beaker containing the cell is -3.8 bars.

so it can be stated that the osmotic pressure of cell is greater than that of the solution present in the beaker as a result the solution of the beaker is hypotonic to the respect of the solute potential of the cell.

As a result water will move into the cell.