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In the 2013 regular baseball season, the Cleveland Indians won 48 fewer then twice as many as they lost. They played 162 regular-season games. How many wins and losses did the team have?

User ARRG
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2 Answers

5 votes

Answer:

The number of Win Games = 92

The number of Loss Games = 70

Step-by-step explanation:

Given in question as :

The total number of games Played = 162

Let the number of Win games = x

And The number of losses games = y

SO , x + y = 162 ........... 1

According to question

x = 2 y - 48 .............2

Fromm eq 1 and 2

(2y - 48 ) +y = 162

3y -48 = 162

or,3y = 210

SO, Y = 70

Similarly x = 2 (70 ) - 48

I.e x = 140 - 48 = 92

Hence The number of Win Games = 92

And The number of Loss Games =70 Answer

Explanation:

User Wenkesj
by
7.3k points
6 votes

Answer:

The number of Win Games = 92

The number of Loss Games = 70

Explanation:

Given in question as :

The total number of games Played = 162

Let the number of Win games = x

And The number of losses games = y

SO , x + y = 162 ........... 1

According to question

x = 2 y - 48 .............2

Fromm eq 1 and 2

(2y - 48 ) +y = 162

3y -48 = 162

or,3y = 210

SO, Y = 70

Similarly x = 2 (70 ) - 48

I.e x = 140 - 48 = 92

Hence The number of Win Games = 92

And The number of Loss Games =70 Answer

User RoyOsherove
by
7.2k points