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What is an equation of the line that passes through the points (-6, -1) and (-8, -4)

User DrRobertz
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Answer:

Explanation:

First consider the equation for the slope. m = (y2 - y1)/(x2 - x1) = (1 - 8)/(6 - 4) = -7/2.Next consider the linear point-slope formula y = mx + b. Choose a point and plug it in (either will do, the result will be the same). 1 = (-7/2)(6) + b = -21 + b -> b = 22 - > y = (-7/2)x + 22 is the equation you desire.

User Megalomono
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