Question

I am confused on how to do either of these problems. Please help

Answer 1

19. a) 48.3 m

b) 88.2 m

20. a) t ≅ 6.38 s

b) ≅270.1 m

Step-by-step explanation:

Use basic linear motion equations for each of these questions, correctly.

s = ut +
`(1)/(2)`a
`t^(2)`

a) applying the equation to the horizontal direction,

s = ut = 11.5×4.2 = 48.3 m ( as gravitational acceleration for horizontal direction is zero)

b) applying the equation to the vertical direction in downward direction,

s = h( height ) =0 +
`(1)/(2)`g
`t^(2)` ( as initial velocity in vertical direction is zero.)

h = 0.5×10×
`4.2^(2)`

=88.2 m

20) Using the same equation,

a) s = ut +
`(1)/(2)`a
`t^(2)` apply it for vertical motion just as it reachs the ground in upwards direction,

0 = usin37°t -
`(1)/(2)`g
`t^(2)`

53(0.6081) = 0.5×10×t

t ≅ 6.38 s

b) again same equation in horizontal direction,

s = ucos37°t = 53×0.7986×6.38

≅270.1 m