Question

One person walks 9/20 miles in each 3/4 hour. Another person walks If a person

walks 8/15 miles in each 2/3 hour. Who is faster?

Answer 1

The second person is walking faster than the first person.

Solution:

Given, One person walks
`(9)/(20)` miles in each
`(3)/(4)` hour.

Another person walks
`(8)/(15)` miles in each
`(2)/(3)` hour.

We have to find who is walking faster?

Now, we know that, distance = speed x time

Let us find the speed of each person

Speed of first person:

`\begin{array}{l}{\text { Speed of } 1 \mathrm{st} \text { person } \rightarrow (9)/(20)=\text { speed } * (3)/(4)} \\\\ {\rightarrow (9)/(20) * (4)/(3)=\text { speed }} \\\\ {\rightarrow \text { speed }=(3)/(5)}\end{array}`

Speed of second person:

`\begin{array}{l}{\text { Now, speed of } 2^{\text {nd }} \text { person } \rightarrow (8)/(15)=\text { speed } * (2)/(3)} \\\\ {\rightarrow (8)/(15) * (3)/(2)=\text { speed }} \\\\ {\rightarrow \text { speed }=(4)/(5)}\end{array}`

We know that,
`(3)/(5) < (4)/(5)`

Hence, the second person is walking faster than the first person.