Question

1. A mass is on a level plane, it has a weight of 20N. What is the coefficient of kinetic friction if an applied force

of 8N is sufficient to keep the mass moving with a constant velocity?

Answer 1

0.4

Step-by-step explanation:

F-Fr=ma where F is applied force, Fr is friction, m is mass and a is acceleration.

Since the mass is moving with a constant velocity, there's no acceleration hence

`F=Fr=\mu N` where N is the weight of object and \mu is coefficient of kinetic friction.

`F=\mu N and making [tex]\mu` the subject

`\mu=\frac {F}{N}`

Substituting F for 8 N and N for 20 N

`\mu=\frac {8}{20}=0.4`

Therefore, coefficient of kinetic friction is 0.4