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An object with an initial velocity of 3.2 m/s accelerates at a rate of 1.6 m/s2 for 4 seconds. How far will it have traveled during that time?

1 Answer

4 votes

Answer:

25.6 m

Step-by-step explanation:

From kinetic equation


s=ut +0.5at^(2) where u is initial velocity, a is acceleration and t is time.

Substituting 3.2m/s for u, 1.6m/s2 for a and 4 s for t


s=3.2*4+0.5(1.6*4^(2))=12.8+12.8=25.6 m

Therefore, the distance is 25.6 m

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