Answer:
Van = 18
Bus = 58
Explanation:
Let v be the number of students carried by each van.
Let b be the number of students carried by each bus.
We know the following:
![$\left\{{{16v+8b=752}\atop{5v+5b=380}}$](https://img.qammunity.org/2020/formulas/mathematics/high-school/tst2t32rhujv4n9tinguwetel57jwmc7cz.png)
Solve the second equation for b:
![$5v+5b=380$](https://img.qammunity.org/2020/formulas/mathematics/high-school/2wbmmlkzgow0dcpywfmzf05m8nxumfqa2j.png)
![$5b=380-5v$](https://img.qammunity.org/2020/formulas/mathematics/high-school/dexneb1n2cl9ofb5ftc1dq6buurufr9ej9.png)
![$b=76-v$](https://img.qammunity.org/2020/formulas/mathematics/high-school/g8f3jl3knbttwlovjfj7q0u6rh9eyqkk8z.png)
Replace b with (76 – v) in the first equation:
![$16v+8b=752$](https://img.qammunity.org/2020/formulas/mathematics/high-school/zvrp8sehvtk8yrhvn23kmhqjc40mapnfdt.png)
![16v+8(76-v)=752](https://img.qammunity.org/2020/formulas/mathematics/high-school/jgb6nn15yays78mwenotq9fsw2rjsgpi4p.png)
![16v+608-8v=752](https://img.qammunity.org/2020/formulas/mathematics/high-school/tw8vsakvhz8yctb9zatxf0ip5q8l1ywkwk.png)
![8v+608=752](https://img.qammunity.org/2020/formulas/mathematics/high-school/w05yjxj5j6hboea96zpdf9okwy8mmjatn2.png)
![8v=144](https://img.qammunity.org/2020/formulas/mathematics/high-school/dkw78lrioakjw7tx4spzt5g93fafekbf9n.png)
![v=18](https://img.qammunity.org/2020/formulas/mathematics/high-school/d7qky8g6dcswy0qaa064ypdq6c0xrstmhd.png)
Therefore, each van can carry 18 students. Each bus, then, can carry 76 – v = 76 – 18 = 58.
To verify:
High School A had 16 vans and 8 buses equaling (16 × 18) + (8 × 58) = 288 + 464 = 752. That is correct.
High School B had 5 vans and 5 buses equaling (5 × 18) + (5 × 58) = 90 + 290 = 380. That is correct.