Question

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

Answer 1

150 meters

Step-by-step explanation:

d = .5a*t^2 + v0*t

d = displacement

v0 = initial velocity, 0 because the object was initially at rest

a = acceleration, which is 12

t = time, which is 5

d = (12/2)*(5^2)+0 = 6*25 = 150