Answer:
Point-slope form of a line look like
![\left(Y-Y_(1)\right)=m\left(X-X_(1)\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/56zjcnxkya6cn1jxg3qz4ve5nn9sxfroiw.png)
Explanation:
Point slope form emphasizes the slope of a line and a point on that line. For calculating the slope of a line you need only two points on that line, the two points are
![\left(X_(1), Y_(1)\right) \text { and }(X, Y).](https://img.qammunity.org/2020/formulas/mathematics/middle-school/29s8f8l354roiu8q8m3h6v47kdcrcxpoe1.png)
is a known point, m is the slope of that line and (X, Y) is any other point on the line. Substitute the values,
![m=\frac{\text { change in } Y}{\text { change in } X}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z5pvo2x66snj4j5kig5z7ptcje3t4l7ljk.png)
![m=((Y-Y 1))/((X-X 1))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w50435a20vf5bjdai91xu9x5rleq5z1peg.png)
![\left(Y-Y_(1)\right)=m\left(X-X_(1)\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/56zjcnxkya6cn1jxg3qz4ve5nn9sxfroiw.png)
Therefore the Point-slope form of a line look like
![\left(Y-Y_(1)\right)=m\left(X-X_(1)\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/56zjcnxkya6cn1jxg3qz4ve5nn9sxfroiw.png)