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What does point-slope form look like?

User Thepanuto
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1 Answer

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Answer:

Point-slope form of a line look like
\left(Y-Y_(1)\right)=m\left(X-X_(1)\right)

Explanation:

Point slope form emphasizes the slope of a line and a point on that line. For calculating the slope of a line you need only two points on that line, the two points are
\left(X_(1), Y_(1)\right) \text { and }(X, Y).


\left(X_(1), Y_(1)\right) is a known point, m is the slope of that line and (X, Y) is any other point on the line. Substitute the values,


m=\frac{\text { change in } Y}{\text { change in } X}


m=((Y-Y 1))/((X-X 1))


\left(Y-Y_(1)\right)=m\left(X-X_(1)\right)

Therefore the Point-slope form of a line look like
\left(Y-Y_(1)\right)=m\left(X-X_(1)\right)

User Adriatic
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