Question

PLEASE someone help its due tonight im almost done

Answer 1

Answers:

• 48 seconds
• 3624 feet

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Step-by-step explanation:

x = number of seconds that elapse

y = altitude (aka height) of the plane

The equation for plane A is

y = 20.25x+2652

because it starts off at 2652 ft in the air, and then adds on 20.25 feet per second which is what the 20.25x describes

The equation for plane B is

y = 75.5x

The y intercept is zero because plane B starts on the ground, aka height 0.

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The system of equations is

`\begin{cases}y = 20.25x+2652\\y = 75.5x\end{cases}`

If we want to know when they'll reach the same height (y), then we can set the two right hand sides equal to each other and solve for x.

75.5x = 20.25x+2652

75.5x-20.25x = 2652

55.25x = 2652

x = (2652)/(55.25)

x = 48

The two planes reach the same altitude at exactly 48 seconds

That altitude is 3624 feet because

• y = 20.25*x + 2652 = 20.25*48+2652 = 3624
• y = 75.5*x = 75.5*48 = 3624

Notice I plugged x = 48 into each equation and I got the same y value of y = 3624. This helps confirm the answers.