Question

An 1100kg car reached 30m/s in 9s from rest. What force did the engine provide?

Answer 1

≅3666.67 N

Step-by-step explanation:

Use Newton's 2nd law, F = ma where F=force applied, m = mass of the object,

a = acceleration acquired by the object.

a= (v-u)/t where v = final velocity, u = initial velocity and t = time taken

calculate a = (30-0)/9 ≅ 3.33 m/s2

Then F = 1100×a = 3666.67 N