Answer:
The number of customers needed to break even is
![\simeq 6775.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/akvujgydv2zobciopqysx4utaqnfw7hwt1.png)
Explanation:
Rent per month = $ 7200
Rent per year, $
![7200 * 12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8djv1uv80ccubaucttt92pp9r4vx2zkqyn.png)
= $ 86400 -------------(1)
Insurance per year = $ 4200 ---------(2)
Total direct cost for 2 servers (withoout tax) per year,
= $
![2 * 15 * 8 * 5 * 50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tf23osnyyj8bxcuelyun13tmuj3i7sl0pk.png)
= $ 60000
Total cost for helper ( without tax) per year,
= $
![4 * 15 * 5 * \50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rtitmtzncen6avkioi9crwdn73wdpwwqso.png)
= $ 15000
Total cost for employees per year (without tax),
= $ (60000 +15000) = $ 75000
Total cost per year for employees including tax,
$
![\frac {(75000 * (100 + 6.2 + 1.45)}{100}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qz7r7p6jdahqb2p5mx5bxd5joxv0jad4wp.png)
= $
![\frac {(75000 * 107.65 }{100}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u06ua34lriynw2gawus7z816n94mmal7pd.png)
= $ 80737.5 -----------------------(3)
So,
total cost for running the restaurant (except food)
= (1) + (2) + (3) = $
![(86400 + 4200 + 80737.5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hirne3hsweyo9po3855k6tonfzdcn88okq.png)
= $ 171337.5
Average total profit per customer,
= ( Average per customer payment - average cost of food per customer)
= $ (45.47 - 20.18)
= $ 25.29
So, total number of customer needed to break even,
=
![\frac {171337.5}{25.29}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q9lv10zcbbk4h6am5lw1kjtn88zahdpwr5.png)
\simeq 6775