Question

a 4.50 g coin of copper absorbed 54 calories of heat. what was the final temperature of the copper if the initial temperature was 25°C? the specific heat of copper is 0.092 cal/g°C

Answer 1

Final temperature = T₂ = 155.43 °C

Step-by-step explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of coin = 4.50 g

Heat absorbed = 54 cal

Initial temperature = 25 °C

Specific heat of copper = 0.092 cal/g °C

Final temperature = ?

Solution:

Q = m.c. ΔT

ΔT = T₂ -T₁

Q = m.c. T₂ -T₁

54 cal = 4.50 g × 0.092 cal/g °C × T₂ -25 °C

54 cal = 0.414 cal/ °C × T₂ -25 °C

54 cal /0.414 cal/ °C = T₂ -25 °C

130.43 °C = T₂ -25 °C

130.43 °C + 25 °C = T₂

155.43 °C = T₂