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\frac{ \sqrt{7 + √(24) } } 2{ + } \frac{ \sqrt{7 - √(24) } }{2}


\frac{ \sqrt{7 + √(24) } } 2{ + } \frac{ \sqrt{7 - √(24) } }{2} ​-example-1

1 Answer

2 votes

Answer:

√6

Explanation:

We have to find the value of the expression
\frac{\sqrt{7+√(24) } }{2} +\frac{\sqrt{7-√(24) } }{2}.

Let,
A = \frac{\sqrt{7+√(24) } }{2} +\frac{\sqrt{7-√(24) } }{2}


A^(2) = (7+√(24) )/(4) +(7-√(24) )/(4)+ 2* \frac{\sqrt{7+√(24) } }{2} * \frac{\sqrt{7-√(24) } }{2} {Squaring both sides. Since (a + b)² = a² + b² + 2ab}


A^(2) = (7+√(24)+7-√(24)  )/(4) + 2 * (√(49-24) )/(4) {Since (a + b)(a - b) = a² - b²}


A^(2)= (7)/(2)  +2 * (5)/(4)


A^(2) = (7)/(2) +(5)/(2) = 6

A = √6 (Answer) {Neglecting the negative root as the original expression is positive}

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