Question

Imagine you have a toy box that holds 3 wind-up toys and 5 spinning toys. A toy is taken out of the box and then put back 8 times. A spinning toy is taken out of the box 3 times. What is the experimental probability of drawing a wind-up toy out of the box?

Answer 1

Answer: 5/8

You need to find the probability of getting a wind up toy, 8-3 is 5 so then the fractions 5/8

Answer 2

\
`\frac {3}{5}`

Explanation:

The toy box holds 3 wind-up toys and 5 spinning toys. A toy is taken out of the box and then put back 8 times. It will have no effect.

Next, a spinning toy is taken out of the box 3 times. So, there are now

3 wind-up and
`(5 - 3) = 2` spinning toys.

P(Drawing a wind - up toy out of the box)

=
`\frac {3}{3 + 2}`

=\
`\frac {3}{5}` (Answer)