233k views
0 votes
I have a deck of 54 cards, and I deal all of the cards to x players, with each player getting y cards. If x is at least 2 and y is at least 5, then how many possible values of x are there?

1 Answer

2 votes

Answer:

4 possible values namely, (2 , 3, 6, 9 )

Explanation:

When we factorise 54 we get,


54 = 2 * 3 * 3 * 3

So, factors of 54 are, ( Except 1 and 54 (in pairs))

1. (2 , 27) 2. (3, 18) 3. (6 , 9)

So,

X ∈ {2, 3, 6, 9} but x ∉ { 27 , 18} since y ∉ {2 ,3}

So, there are 4 possible values for x.

User Jon Rosen
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.