Question

2. A force of 156 N acts on a 7.3-kg bowling ball for 0.40 s.

a. What is the bowling ball's change in momentum?

Answer 1

`62.4N\cdot s`

Step-by-step explanation:

The change in momentum of the ball is equal to the impulse exerted on it, therefore:

`\Delta p = I = F \Delta t`

where

`\Delta p` is the change in momentum

F is the average force exerted on the ball

`\Delta t` is the time during which the force is applied

In this problem,

F = 156 N

`\Delta t = 0.40 s`

So, the change in momentum of the ball is

`\Delta p =(156)(0.40)=62.4N\cdot s`