Question

A line that includes the points (6,h) and (7,−10) has a slope of −7. ​ ​ What is the value of h ? ​

Answer 1

the answer is h= -3

Explanation:

add 7 to -10 to find the value of h

Answer 2

-3

Explanation:

You can use
`(y_2-y_1)/(x_2-x_1)` to find the slope of a line going through
`(x_1,y_1)` and
`(x_2,y_2)`.

I like to line up the points and subtract vertically. Then put 2nd difference over 1st difference.

(6,h)

minus

(7,-10)

------------

-1 h-(-10)

`(h-(-10))/(-1)`

This also said to be equal to -7:

`(h+10)/(-1)=-7`

Multiply -1 on both sides:

`h+10=7`

Subtract 10 on both sides:

`h=7-10`

[texh=-3[/tex]

So if h=-3 then the slope of the line going through (6,h) and (7,-10) is -7.

Let's test it:

(6,-3)

minus

(7,-10)

----------

-1 7

So the slope is 7/-1=-7. This is the intended goal.

The check is good.