Question

Evaluate the trigonometric ratio​

Answer 1

1

Explanation:

Given
`\lim_(x \to 0) (sinxcosx)/(x)`

multiply the numerator and denominator with 2

we get
`\lim_(x \to 0) (2sinxcosx)/(2x)`

We know that sin2x=2sinxcosx

`\lim_(x \to0) (sin2x)/(2x)`

Now consider y=2x

As x→0 2x→0 y→0

Now limit changes to

`\lim_(y \to0) (siny)/(y)`=1