Question

1.Complete the table. f(x) = e^(-x)

2. Use log 2 = a, log 3 = b to evaluate log (12).

Answer 1

f(-3) = 20.08

f(3) = 0.049

log 12 = 2a + b

Explanation:

1. Given that
`f(x) = e^(-x)`

Therefore,
`f(-3)=e^(-(-3)) = e^(3) = 20.08`

Again,
`f(3) = e^(-3)=0.049`

2.
`\log 12= \log (4 * 3)= \log 4 + \log 3 = \log 2^(2) +\log 3 = 2\log 2 +\log 3` {Since log ab =log a + log b and log a² = 2 log a}

So,
`\log 12 = 2a+b` {Since log 2 =a and log 3 = b given}