122k views
4 votes
Find (f+g)(3), (f-g)(3), (fg)(3), and (f/g)(3) for f(x)=x+3, g(x)=x^2

User Sharondio
by
8.0k points

1 Answer

5 votes

Answer:

15, -3, 54, 2/3

Explanation:

We have:


f(x)=x+3\\g(x)=x^2


(f+g)(x) can be calculated as


(f+g)(x)=f(x)+g(x)

So in this case,


(f+g)(x)=x+3+x^2

And substituting x = 3,


(f+g)(3)=3+3+3^2=15


(f-g)(x) can be calculated as


(f-g)(x)=f(x)-g(x)

So in this case,


(f-g)(x)=x+3-x^2

And substituting x = 3,


(f+g)(3)=3+3-3^2=-3


(fg)(x) can be calculated as


(fg)(x)=f(x)g(x)

So in this case,


(fg)(x)=(x+3)(x^2)=x^3+3x^2

And substituting x = 3,


(fg)(3)=3^3+3\cdot 3^2=54


(f/g)(x) can be calculated as


(f/g)(x)=(f(x))/(g(x))

So in this case,


(f/g)(x)=(x+3)/(x^2)

And substituting x = 3,


(f/g)(3)=(3+3)/(3^2)=(2)/(3)

User Joel Falcou
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories