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A fair coin is tossed three times in succession. The set of equally likely outcomes is {HHH, HHT, HTH, THH, HTT, THT, TTH TTT}. Find the probability of getting exactly two heads

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Answer: 0.375

Explanation:

Let x be the event that at exactly 2 heads occurs

Let s be the sample space

Therefore;

n(s) = 8

n(x) = 3 (HHH, HHT, THH)

p(x) = n(x)/n(s)

p(x) = 3/8

p(x) = 0.375

User Nemanja Todorovic
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