Question

How many grams of hydrogen are needed to produce 1.80g of water according to this equation?

2H2+O2 to 2H2O

Answer 1

0.2g of hydrogen is needed to produce 1.80g of water

Step-by-step explanation:

`$H_(2)+O_(2) \to 2H_(2)O$`

No. of moles of water
`$= (Weight)/(Molecular \, weight)$ \\`

From given values,

Weight of water
`$=1.80g$`

Molecular weight of water
`$=18g$`

`$\therefore$` No. of moles of water
`$=(1.80)/(18)=0.1 $`

From equation, it is clear that 2 moles of water can be formed by 2 moles of
`$H_(2)$`

Hence, 0.1 mole of water can be formed from 0.1 mole of
`$H_(2)$`

Now,

No. of moles of
`$H_(2) = (Weight)/(Molecular \, weight)$`

`$\Rightarrow weight \,of\, H_(2)=No.\,of\,moles * Molecular\,weight$\\ $=0.1 * 2=0.2g$`