Question

A data analyst has spreadsheets numbered

1

,

2

, databases numbered

1

,

2

,

3

, and presentations numbered

1

,

2

,

3

,

4

to work on this week. If a single item is picked at random to work on, what is the probability that the item is a database AND has an odd number?


Provide the final answer as a fraction. PLEASE HELP ASAP!

Answer 1

`(2)/(9)`

Explanation:

`{\textrm}{Total number of objects here} = 9`

(2 spreadsheets, 3 databases and 4 presentations,

`{\textrm}({Total} = 2+3+4 = 9</strong>)<strong>`

`{\textrm}{No. of databases with an odd number} =</strong> <strong>2 {\textrm}{(databases with number 1 and 3})`

As not mentioned other wise equal chances of all the outcomes is assumed so, by the classical definition of probability,

P(The chosen item is a odd numbered database)

=
`(2)/(9)`