Answer:
A) Marie can afford Car expensive of = $2139
B)The total amount she pay to loan company = $ 3000
C) The interest amount = $861
Explanation:
Given as :
Marie can afford car payment of =$ 250 per month
=$ = 250 × 12 = $3000 per year
She Found a loan for time period of = 5 years
The interest rate applied = 7%
Now ,
Amount of payment = Principal ×
![( 1+ (Rate)/(100))^(Time)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nyuq6zplbtbiteks2c27ikkqrshx5hhy5a.png)
Or, $3000 = The original value of car ×
![( 1+ (7)/(100))^(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rhvg4sqt9yfsmoksoncnihpnwij3efbn33.png)
Or, $3000 = The original value of car × 1.4025
Or, The original value of car =
![(3000)/(1.4025)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5gnp0l1ffsispmxelx2momu7saegxrey2w.png)
So, The original value of car = $2139.03
Now, Compound Interest = CI = Amount - Principal
Or, CI = $3000 - $2139
So, CI = $861
Hence Form the above solution, it is found that :
A) Marie can afford Car expensive of = $2139
B)The total amount she pay to loan company = $ 3000
C) The interest amount = $861 Answer