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Find the equation of a line perpendicular to y=−4x−1 that contains the point (−2,2). Write the equation in slope-intercept form.

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Answer:

see explanation

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 4x - 1 ← is in slope- intercept form

with slope m = - 4

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(-4) =
(1)/(4), thus

y =
(1)/(4) x + c ← is the partial equation of the line

To find c substitute (- 2, 2) into the partial equation

2 = -
(1)/(2) + c ⇒ c =
(5)/(2)

y =
(1)/(4) x +
(5)/(2) ← in slope- intercept form

User Kjgilla
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