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Solve 3x^2 = -12x - 15

User Oben Sonne
by
5.3k points

2 Answers

3 votes

The answer is no real solution

Explanation:

Let's solve your equation step-by-step.

3x2=−12x−15

Step 1: Subtract -12x-15 from both sides.

3x2−(−12x−15)=−12x−15−(−12x−15)

3x2+12x+15=0

Step 2: Use quadratic formula with a=3, b=12, c=15.

x=

−b±√b2−4ac

2a

x=

−(12)±√(12)2−4(3)(15)

2(3)

x=

−12±√−36

6

User Miriam Salzer
by
5.4k points
4 votes

The solutions of the quadratic equation are:


x = -2 \pm i

Let's solve the equation:

Here we have the quadratic equation:

3x² = -12x - 15

We can rewrite this as:

3x² + 12x + 15 = 0

Divide all by 3:

(3x² + 12x + 15) = 0

x² + 4x + 5 = 0

Now we can use the quadratic formula to get:


x = (-4 \pm √(4^2 - 4*1*5) )/(2) \\\\x = (-4 \pm 2i )/(2) \\\\x = -2 \pm i

User Reo Katoa
by
5.6k points