Question

One section of a pipe carrying water has a cross-sectional area of 20 cm2; in this section the water has flow velocity of 1.0 m/s. Another section of this pipe has a constricted cross-sectional area of 5 cm2. If the flow is steady, what is the water velocity in the constricted section?

Answer 1

v₂ = 4 m/s

Step-by-step explanation:

A₁ = 20 cm²

v₁ = 1 m/s

A₂ = 5 cm²

v₂ = ?

If the flow is steady

Q₁ = Q₂ = Q

⇒ v₁*A₁ = v₂*A₂ ⇒ v₂ = v₁*A₁ / A₂

⇒ v₂ = (1 m/s)(20 cm²) / (5 cm²) = 4 m/s