Question

In a lab experiment, two identical gliders on an air track are held together by a piece of string, compressing a spring between the gliders. While they are moving to the right at a common speed of 0.420 m/s, one student holds a match under the string and burns it, letting the spring force the gliders apart. One glider is then observed to be moving to the right at 1.300 m/s. (the string and spring both have negligible mass). What velocity does the other glider have? Enter a positive value if the velocity is toward right and enter a negative value if the velocity is toward left.

Answer 1

`v_(1f)` = -0.460 m/s

Step-by-step explanation:

To solve this problem we will use the concept of moment, write the initial amount when they are united and the end

Initial. Before break away

p₀ = (m + m) v₀

Final. After separating

`p_(f)` = m
`v_(1f)` + m
`v_(2f)`

p₀ =
`p_(f)`

(m + m) v₀ = m
`v_(1f)` + m
`v_(2f)`

They tell us that when they go together the speed vo = 0.420 m / s and after separating one we will call 2 has a speed of v2f = 1,300 m / s. let's look for each other's speed

m
`v_(1f)` = (2m) vo - m
`v_(2f)`

`v_(1f)` = 2 v₀ -
`v_(2f)`

`v_(1f)` = 2 0.420 - 1.300

`v_(1f)` = -0.460 m/s

The negative sign indicates that it moves to the left