Answer:
The probability that the student answers all questions incorrectly is 0.1074
The probability that the student will achieve at least 50% correct is 0.0328
Explanation:
This exercise adjust to a normal distribution, where:
p: probability that the student answers the question correctly (
)
n: number of questions (10 questions)
The binomial distribution is given by:
![P(X=x)=(n!)/(x!(n-x)!)* p^x * (1-p)^(n-x)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ro5jotfkhqltaq4wzykfs4dxih39zc9j4a.png)
The probability that the student answers all questions incorrectly is P(X=0)
![P(X=0)=(10!)/(0!(10-0)!)* (0.2)^0 * (1-0.2)^(10-0)=0.1074](https://img.qammunity.org/2020/formulas/mathematics/high-school/8clw1atolzkg0j2lkzgaam4d8tdfu0abc5.png)
The probability that the student will achieve at least 50% correct is P(X≥5)
P(X≥5)= 1 - P(X=0) - P(X=1) - P(X=2) - P(X=3) - P(X=4)
P(X=0)=0.1074
![P(X=1)=(10!)/(1!(10-1)!)* (0.2)^1 * (1-0.2)^(10-1)=0.2684](https://img.qammunity.org/2020/formulas/mathematics/high-school/xb4t7aztz32t4k5wz32b8lqohkwjjw5j5d.png)
![P(X=2)=(10!)/(2!(10-2)!)* (0.2)^2 * (1-0.2)^(10-2)=0.3020](https://img.qammunity.org/2020/formulas/mathematics/high-school/2er1ocmi9atesgl10p9n882qa4fhkyoddn.png)
![P(X=3)=(10!)/(3!(10-3)!)* (0.2)^3 * (1-0.2)^(10-3)=0.2013](https://img.qammunity.org/2020/formulas/mathematics/high-school/qzgrcbbeawijqopwlu3wgggl1p1dgolo98.png)
![P(X=4)=(10!)/(4!(10-4)!)* (0.2)^4 * (1-0.2)^(10-4)=0.0881](https://img.qammunity.org/2020/formulas/mathematics/high-school/veni0g36iq3p8el0levsgkul4eflaw0bfq.png)
P(X≥5)= 1 - 0.1074 - 0.2684 - 0.3020 - 0.2013 - 0.0881=0.0328