Answer:
The probability that the student answers all questions incorrectly is 0.1074
The probability that the student will achieve at least 50% correct is 0.0328
Explanation:
This exercise adjust to a normal distribution, where:
p: probability that the student answers the question correctly (
)
n: number of questions (10 questions)
The binomial distribution is given by:

The probability that the student answers all questions incorrectly is P(X=0)

The probability that the student will achieve at least 50% correct is P(X≥5)
P(X≥5)= 1 - P(X=0) - P(X=1) - P(X=2) - P(X=3) - P(X=4)
P(X=0)=0.1074




P(X≥5)= 1 - 0.1074 - 0.2684 - 0.3020 - 0.2013 - 0.0881=0.0328