Answer:
def haigyPaigy(dict, text):
# Create a regular expression from the dictionary keys
regex = re.compile("(%s)" % "|".join(map(re.escape, dict.keys())))
# For each match, look-up corresponding value in dictionary
return regex.sub(lambda mo: dict[mo.string[mo.start():mo.end()]], text)
text = input("Enter text: ")
dict = {
"a" : "aiga",
"e" : "aige",
"i" : "aigi",
"o" : "aigo",
"u" : "aigu",
}
print(haigyPaigy(dict, text))
Step-by-step explanation:
Step 1:
define the haigyPaigy function: this function takes its argument from a dictionary and the text you you want to convert.
def haigyPaigy(dict, text):
In the function, there are two regular expressions:
- regex = re.compile("(%s)" % "|".join(map(re.escape, dict.keys())))
this is a regular expression for the dictionary keys, it looks through the text for a match, it acts like a scanner, simply put, it looks for [a,e,i,o,u].
re.compile(pattern, repl, string): is used to combine a regular expression pattern into pattern objects, which can be used for pattern matching. It also helps to search a pattern again without rewriting it.
- return regex.sub(lambda mo: dict[mo.string[mo.start():mo.end()]], text)
For each match, it looks up the key in the dictionary and replaces it with a corresponding value.
Step 2:
prompt the user to input the text that needs conversion to Haigy Paigy
text = input("Enter text: ")
Step 3:
Create the dictionary by inputting the key and the corresponding value.
NOTE: the key is what you want to replace in the text and the value is what you're replacing it with.
dict = {
"a" : "aiga",
"e" : "aige",
"i" : "aigi",
"o" : "aigo",
"u" : "aigu",
}
Step 4:
Call the function and print the translated text to your screen.
print(haigyPaigy(dict, text))