Question

A person is involved in a car crash and has a momentum of 2,050 kg*m/s. If the airbag deploys, the impact will occur over 0.1 seconds. If the airbag does NOT deploy, the impact will occur over 0.01 seconds. How will the impact force change if the airbag does NOT deploy?

Answer 1

The force will be 10 times greater.

Step-by-step explanation:

The force is calculated as:

`F=(\Delta P)/(\Delta t)`

If the airbag deploys:

F1 = 2.050 / 0.1 = 20.5 N

And if it doesn't:

F2 = 2.050 / 0.01 = 205N

As you can see, F2 is 10 grater than F1