Question

Compute the total resistance of a parallel circuit in which one branch has a resistance of 40 ohms and the other has a resistance of 60 ohms

Answer 1

The total resistance of a parallel circuit is 24 ohms

Step-by-step explanation:

The total resistance of a parallel circuit where resistance is given by

`$\frac{1}{\mathrm{Rt}}=\frac{1}{\mathrm{R} 1}+\frac{1}{\mathrm{R} 2}+\frac{1}{\mathrm{R} 3}+\frac{1}{\mathrm{R} 4}$`… and so on

Where Rt = Total resistance and R1, R2, R3 etc. are resistances attached in parallel

We are given, R1 = 60 ohms and R2 = 40 ohms

So Rt will be given by

`$\frac{1}{\mathrm{Rt}}=(1)/(60)+(1)/(40)$`

Solving this we get

Rt =
`$((60 * 40))/((60+40))$` = 24

Which gives Rt = 24 ohms which is the required total resistance.