Answer:
16.02kW and 12.91kW
Step-by-step explanation:
Knowing the enthalpy data, we have to
![h1=239.16kJ/kg\\h2=296.81kJ/kg](https://img.qammunity.org/2020/formulas/engineering/college/27sj0z9bszhr2su08lxw0khume8qfd19yp.png)
So,
![E_(mass,in)=mh_1](https://img.qammunity.org/2020/formulas/engineering/college/vkm7p3ml997b85otcqjdvrl3hzxjy6oo02.png)
Here,
m=mass flow rate
h= Enthalpy of refrigerant at the compressor
Replacing
![E_(mass,in)=(0.054Kg/s)(239.16kJ/kg)\\E_(mass,in)=12.91kW](https://img.qammunity.org/2020/formulas/engineering/college/fxrxvwfmtt9wt2s0bhiyjdoi0qzoups2gi.png)
The rate of energy transfer by mass into the compressor is 12.91kW
In the other hand we have,
![E_(mass,out)=mh_2](https://img.qammunity.org/2020/formulas/engineering/college/5y1xfra5i5klvmb9iae4zv0xacf9aantgm.png)
Replacing
![E_(mass,out)=(0.054Kg/s)(296.81kJ/kg)\\E_(mass,out)=16.02kW](https://img.qammunity.org/2020/formulas/engineering/college/xrnlby61zdp4qxmn9su9cv1m7of0axm3s9.png)
The rate of energy transfer by mass out of the compressor is 16.02 kW