Answer:
The critical value is ±2.145
Explanation:
Consider the provided information.
A researcher matched 30 participants on intelligence (hence 15 pairs of participants).
That means the value of n is 15.
Now find the degree of freedom as:
![df=n-1](https://img.qammunity.org/2020/formulas/mathematics/college/j1o31vd0i1oymirsuml5m5vsnq4sg65ruj.png)
Therefore,
![df=15-1=14](https://img.qammunity.org/2020/formulas/mathematics/high-school/3s9zommi0vdawz1ncsuk4iyncin8kuy15o.png)
It is given that assuming a two-tailed test at a 0.05 level of significance.
α=0.05
![(\alpha)/(2)=(0.05)/(2)=0.025](https://img.qammunity.org/2020/formulas/mathematics/high-school/da7ssrwyedar9nqo4r5xxmtc1rv5wsay47.png)
Now by using t distribution table the critical value is:
![\pm t_{(\alpha)/(2),df}=\pm t_(0.025,14)\\\pm t_(0.025,14)\approx\pm2.145](https://img.qammunity.org/2020/formulas/mathematics/high-school/brbp41887ppoojhbg42tssk8dbifvcjslx.png)
Hence, the critical value is ±2.145