Question

What is the completely factored form of 2x2 – 32?

(2x2 + 16)(x - 16)
o 2(x+4)(x-4)
2(x + 3)(x – 4)
2(x - 3)(x – 4)

Answer 1

Answer: 2(x + 4)(x – 4)

Step-by-step explanation: just took the test

Answer 2

The completely factored form of
`2x^(2)  - 32` =
`2(x+ 4)(x-4)`

Explanation:

Here, the given expression is :
`2x^(2)  - 32 = 0`

Now, simplifying the given expression , we get

`2x^(2)  - 32` =
`2(x^(2)  - 16)`

Now, by ALGEBRAIC IDENTITY, we know that

`a^(2) - b^(2)  = (a+b)(a - b)`

So, here
`x^(2) - (4)^(2)  = (x+4)(x - 4)`

⇒
`2(x^(2)  - 16)` =
`2(x+ 4)(x-4)`

Hence, the completely factored form of
`2x^(2)  - 32` =
`2(x+ 4)(x-4)`