Question

A light, inextensible cord passes over a light, frictionless pulley with a radius of 15 cm. It has a(n) 12 kg mass on the left and a(n) 4.1 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 3.3 m apart. The acceleration of gravity is 9.8 m/s 2 . 3.3 m 15 cm ω 12 kg 4.1 kg At what rate are the two masses accelerating when they pass each other? Answer in units of m/s 2 .

Answer 1

5.04m/s^2

Step-by-step explanation:

We define the variables like this,

`m_1 = 15Kg`

`m_2 = 4.8Kg`

`g= 9.8m/s^2`

`a= Acceleration`

We know that the rate is gived for the equation,

`a = (F_(net))/(m_(Total))`

`a= ( ( m1 - m2 ) g)/( (m1 + m2 ))`

`a= \frac {10.2 ( 9.8 )}{19.8} = 5.04m/s^2`