Answer:
![r = k . [CO] .[Cl_(2)]](https://img.qammunity.org/2020/formulas/chemistry/college/i9pjd807f8jq02o40ilu0q51jk9l15cs0g.png)
Step-by-step explanation:
Let´s consider the following reaction:
CO + Cl₂ ⇒ COCl₂
The general rate law is:
![r = k . [CO]^(m). [Cl_(2)]^(n)](https://img.qammunity.org/2020/formulas/chemistry/college/jnyba05jd5b5u9newozuwce3zllj7ucmug.png)
where,
r is the rate of the reaction
k is the rate constant
[CO] and [Cl₂] are the molar concentrations of each reactant
m and n are the reaction orders for each reactant
Since the reaction is first order in CO, m = 1. The overall order is the sum of all the individual orders. In this case, the overall order m + n = 2. Then,
m + n = 2
n = 2 - m = 2 - 1 = 1
The reaction is first order in Cl₂.
The rate law is:
![r = k . [CO]. [Cl_(2)]](https://img.qammunity.org/2020/formulas/chemistry/college/lejv9zczejnw16zcn4oqam0ecm1jybrvgq.png)