Question

In the simple Bohr model of the ground state of the hydrogen atom, the electron travels in a circular orbit around a fixed proton. The radius of the orbit is 5.28 × 10−11 m, and the speed of the electron is 2.18 × 106 m/s. The mass of an electron is 9.11 × 10−31 kg . What is the force on the electron?

Answer 1

B = - 234789.373 Tesla

Step-by-step explanation:

radius of the orbit (r):

• r = m*ν / q*B = 5.28 E-11 m

∴ q = - 1.602 E-19 C...elementary electric charge

∴ m = 9.11 E-31 Kg.....mass of electron

∴ ν = 2.18 E6 m/s...speed of the electron

∴ B: magnetic force on the electron

⇒ B = m*v / q*r

⇒ B = ((9.11 E-31 Kg)*(2.18 E6 m/s)) / ((-1.602 E-19 C)*(5.28 E-11 m))

⇒ B = - 234789.373 Kg / C.s

⇒ B = - 234789.373 T