Question

12(a+3)^3+4(a+3) factorise​

Answer 1

4(a + 3)(3a² + 18a + 28)

Explanation:

Given

12(a + 3)³ + 4(a + 3) ← factor out 4(a + 3) from each term

= 4(a + 3) [ 3(a + 3)² + 1 ]

= 4(a + 3)(3a² + 18a + 27 + 1)

= 4(a + 3)(3a² + 18a + 28)

Answer 2

4 ( a +3 )( 3 a 2 + 18 a + 28 )

Explanation:

Factor

4 ( a + 3 ) out of 12 ( a + 3 )3 + 4 ( a + 3 )

Next Step

4 ( a + 3 ) ( 3 ( a + 3 ) 2 + 1 )

Rewrite

( a + 3 ) 2 as ( a + 3 ) ( a + 3 ) .

Next Step

4 ( a + 3 ) (3 ( ( a + 3 ) ( a + 3 ) ) + 1 )

Expand

( a + 3 ) ( a + 3 )

using the FOIL Method.

4 ( a + 3 ) ( 3 (a ⋅ a + a ⋅ 3 + 3 a + 3⋅ 3 ) + 1 )

Simplify and combine like terms.

4 ( a + 3 ) ( 3 ( a 2 + 6 a + 9 ) + 1 )

Apply the distributive property.

4 ( a + 3 ) ( 3 a 2 + 3 ( 6 a ) + 3 ⋅ 9 + 1 )

Simplify.

4 ( a + 3 ) ( 3 a 2 + 18 a + 27 + 1 )

Add

27 and 1 .

4 ( a + 3 ) ( 3 a 2 + 18 a + 28 )

Glad I could help!!