Answer:
![-22.7 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/bje1bj25gt57nj8ahyz5pkrv3mxo4jp142.png)
Step-by-step explanation:
This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:
![v^2-u^2=2as](https://img.qammunity.org/2020/formulas/physics/middle-school/kzr98dbu2wfj2ipzjwf8lasb185fsfra2y.png)
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the car in this problem,
u = 27.8 m/s
v = 0
s = 17 m
Solving for a, we find the acceleration:
![a=(v^2-u^2)/(2s)=(0-27.8^2)/(2(17))=-22.7 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/d0xgs3i7zl20szvqq7zhffnutpqualawwe.png)