Question

How to solve this equation: ax² - 5x + 2 = 0

Answer 1

`x=\frac{5(+/-)√(25-8a)} {2a}`

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`ax^(2) -5x+2=0`

so

`a=a\\b=-5\\c=2`

substitute in the formula

`x=\frac{5(+/-)\sqrt{-5^(2)-4(a)(2)}}{2a}`

`x=\frac{5(+/-)√(25-8a)} {2a}`