Question

H=3 ft and S=16 ft. A 100lb box requires a 35 lb effort force to push the box up the inclined plans. How do I calculate the IMA?​

Answer 1

5.33

Step-by-step explanation:

I assume the following:

H = 3 ft is the height of the ramp

S = 16 ft is the length of the ramp

For an inclined plane, the IMA (Ideal Mechanical Advantage) is given by

`IMA=(S)/(H)`

where

S is the length of the ramp

H is the height

Substituting the data of this ramp, we find

`IMA=(16)/(3)=5.33`

The IMA corresponds to the maximum mechanical advantage that can be achieved on the ramp. In reality, there are always frictional forces acting on the object loaded, therefore the Actual Mechanical Advantage (AMA) is given by

`AMA=(Load)/(Effort)`

where in this case,

L = 100 lb is the load

E = 35 lb is the effort

So for this ramp, the AMA is

`AMA=(100)/(35)=2.86`