Question

A 5 kg weight is hung from a vertical spring. The spring stretches by 5 cm. How much mass should be hung from the spring so it will stretch by 10

cm from its original length?
15 kg
25 kg
10 kg
20 kg

Answer 1

10 kg

Step-by-step explanation:

F = kx

(5 kg) (9.8 m/s²) = k (0.05 m)

k = 980 N/m

F = kx

m (9.8 m/s²) = (980 N/m) (0.10 m)

m = 10 kg