Question

Which equations represent the line that is parallel to 3x - 4y = 7 and passes through the point (-4,-2)? Select two

options.
y=-3x+1
3x - 4y = -4
4x - 3y = -3
Dy-2=-2(x-4)
y+2 = (x + 4)

Answer 1

3x-4y=-4 and y+2= 3/4 (xt4)

Explanation:

b and e

Answer 2

The equation of another line with given points and parallel to the first line is 3X - 4Y = - 4

Explanation:

Given as ,

The equation of one line is 3x - 4y = 7

Or, 4y = 3x - 7

Or, y =
`(3)/(4)`x -
`(7)/(4)`

This line is in the form of y = mx + c

So, slop of this line is ( m 1 ) =
`(3)/(4)`

Now the another line is parallel to this line ,

So, for parallel line condition, slop are equal

i.e (m 1) = ( m 2) , Let (m 2) is the slop of another line .

So , (m1 ) = (m2) =
`(3)/(4)`

Again, the another line with slop (m2) passes through points ( - 4 , - 2)

So , equation of another line is

Y - y1 = (m2) (X - x1)

Or, Y + 2 =
`(3)/(4)` + (x + 4 )

Or, 3X - 4Y = - 4

Hence the equation of another line with given points and parallel to the first line is 3X - 4Y = - 4 Answer