Question

A car is traveling at a velocity of 30 m/s. It then brakes over a displacement of 50 meters to come to rest. What was the acceleration of the car?

Answer 1

The acceleration of the car is
`9 m / \sec ^(2)`

Step-by-step explanation:

Given:

Final velocity v = 0 m/s

Initial velocity u = 30 m/s

Stopping distance or displacement = 50 meters

To Find:

Acceleration of the car=?

Solution:

The third equation of motion is,

`v^(2)-u^(2)=2 a s`

Substituting the known values,

`v^(2)-u^(2)=2 a s`

`(30)^(2)-(0)^(2)=2(a)(50)`

`900=100 a`

`a=(900)/(100)`

`a=9 m / \sec ^(2)`